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2x-3x^2-39x+20=0
We add all the numbers together, and all the variables
-3x^2-37x+20=0
a = -3; b = -37; c = +20;
Δ = b2-4ac
Δ = -372-4·(-3)·20
Δ = 1609
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-37)-\sqrt{1609}}{2*-3}=\frac{37-\sqrt{1609}}{-6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-37)+\sqrt{1609}}{2*-3}=\frac{37+\sqrt{1609}}{-6} $
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